Number of 0 < k < n-2 with p = φ(k) + φ(n-k)/2 + 1 and p_p - p ± 1 prime
Conjecture: a(n) > 0 for all n > 31.
Formal Conjectures is an open repository, started by Google DeepMind, of conjectures stated in Lean 4 with Mathlib. Every open problem from it that we import keeps its exact Lean statement, so a proof submitted here is checked by the Lean kernel against that statement. The collection covers Erdős problems, OEIS conjectures, Ben Green's open problems, Wikipedia's lists of unsolved problems, MathOverflow questions and more.
Source: google-deepmind/formal-conjectures. Licence: Apache License 2.0.
Conjecture: a(n) > 0 for all n > 31.
Conjecture: (i) a(n) > 0 for all n > 8.
Conjecture: For every x ≥ 0, there is an i such that a(n) > x for all n > i.
Conjecture (Peter Bala, 2022): The supercongruences a(n · p^k) ≡ a(n · p^k-1) pmodp^3k hold for the integer-indexed extension a(n) for all n ∈ ℤ ∖ 0, primes p ≥ 5, and k ≥ 1.
Conjecture: all items for n ≥ 4 are greater than or equal to 1. This is a stronger conjecture than the Goldbach conjecture.
Conjecture: let p ≤ n be prime. If m and p^a m are two such products, then so is p^k m for all 0 < k < a. - Yan Sheng Ang, Feb 13 2020
n=1 and 32 are two fixed points. Are there any others?
Conjecture (i): a(n) > 0 for all n > 1.
Conjecture (i): a(n) > 0 if n is not a divisor of 6.
Conjecture: a(n) > 0 for all n > 2.
Conjecture (i): a(n) > 0 for all n > 0.
Conjecture: a(n) > 0 for all n > 0. - _Zhi-Wei Sun_, Dec 29 2012
It is conjectured that a(n)>0 for all n>122. Proving this would also prove Legendre's conjecture that there is a prime between n^2 and (n+1)^2. - _T. D. Noe_, Feb 28 2007
Conjecture (i): a(n) > 0 for all n > 1.
(25,27) is the smallest pair of prime powers (q,q+2) such that both q and q+2 are not primes, conjecture: there are more (but not < 10^6).
It is conjectured that a(n) ≤ 2 for all n.
Conjecture: all the numbers Σ_i=j^k 1/a(i) with 1 < j ≤ k have pairwise distinct fractional parts. - Zhi-Wei Sun, Sep 24 2015
Conjecture (i): for any integer k > 2, the sequence π(n^k)/n^k (n = 2, 3, …) is strictly decreasing, where π(x) denotes the number of primes not exceeding x. - Zhi-Wei Sun, Oct 17 2015
Conjecture: For every n > 4765516, a(n) > 0.
Conjecture: For every n > 13, a(n) > 0.
Conjecture: a(n) < n for n > 13.
Conjecture: all terms of this sequence are greater than 0. - _Lei Zhou_, Oct 05 2011
Conjecture: a(n) > 0 for all n > 3.
Conjecture (i): a(n) > 0 unless n divides 6.
Conjecture (i): a(n) > 0 for all n > 5.
For any n > 0, is there always at least one prime p such that 2^n ≤ p ≤ 2^n + prime(n)? (checked up to n = 250).
Question: for any n > 0, is there at least one prime p such that n^n ≤ p ≤ n^n + n^2? In this case, that would be stronger than the Schinzel conjecture: "for m > 1 there's at least one prime p such that m ≤ p ≤ m + log(m)^2" since n^2 < log(n^n)^2 = n^2 log(n)^2.
Colton's conjecture [Co99] as stated by Zelinsky [Ze02]: for every n, the number of refactorable numbers ≤ n is at least half the number of primes ≤ n, i.e. π(n) ≤ 2 T(n).
n^2 ≡ 1 pmoda(n)(a(n)-1) if and only if n is an odd prime. - Thomas Ordowski, Jun 08 2017
It is conjectured that 1,2,3,4,5,6,7,9,11 are the only positive integers which cannot be represented as the sum of two elements of indices n such that a(n) = 1.
Conjecture: a(n) > 0 for all n > 1.
In April 2009, _Zhi-Wei Sun_ conjectured that a(n) > 0 for every n = 0, 1, 2, 3, ….
Conjecture (i): a(n) > 0 for all n > 2.
Conjecture: If n > 200 is not among 211, 226, 541, 701, then a(n) > 0. - _Zhi-Wei Sun_, Jan 03 2013
Conjecture from N. J. A. Sloane: a(n) > 0 for n > 15.
Conjecture: the sequence A228828 is infinite.
Is 1155 the last odd number in this sequence? (1155 is the 59th term starting from 1, corresponding to a(58) = 1155).
Conjecture: Except for the first term all terms are even.
We conjecture that u(p-1) == 0 (mod p^4) for all primes p, with a finite number of exceptions that depend on m.
Conjecture: if an integer n > 1 is odd, then ζ(2n)/ζ(n)^2 is irrational. Cf. W. Kohnen (link) and my conjecture in A348829. - Thomas Ordowski, Jan 05 2022
Conjecture: for n > 3, textrmnumerator(-2/n + Σ_k=1^n 2^k/k) == 0 (textrmmod n^2) if and only if n is prime.
Conjecture: Consider the sequence b(n) such that b(1)=2, b(2)=3, and for n ≥ 3, b(n)=a(n-2). If we apply the Eratosthenes-like sieve to b(n) and remove 1s, then we obtain a sequence of primes. - _Vladimir Shevelev_, Dec 12 2014
Shevelev conjectures that a(n) ≥ 0 for n > 3.
Special case in dimension 6: determine the maximal number of mutually unbiased orthonormal bases in ℂ^6.
Benchmark open subproblem: existence of a SIC-POVM in dimension 56.
Open benchmark statement: does an AME(8,4) state exist?
Are Fermat numbers composite for all n > 4?
Are e and π algebraically independent?
e + π is transcendental.
For every integer x ≥ 2 there exists a prime between x(x-1) and x^2.
Conjecture: (i) a(n) > 0 for all n > 2.
Conjecture: For each d = 1, 2, 3, … there is a positive integer N(d) for which any integer n > N(d) can be written as k + m with k > 0 and m > 0 such that p_k + 2d and p_p_m + 2d are both prime.
"Ore conjectured that 1 is the only odd harmonic number." Reference: A001599
What is the smallest square that can contain 11 unit squares? Reference: Wikipedia
Conjecture: a(n) > 0 for all n > 1.
The natural density of n where the partition number p(n) is even (resp. odd) exists and equals 1/2.
"On May 16 2012, Zhi-Wei Sun conjectured that a(n) is positive for each n > 4." - _Zhi-Wei Sun_, May 19 2012
Conjecture: For any positive integer n, the polynomials Sum_k=0^n binomial(2k,k)^2x^k and Sum_k=0^n binomial(2k,k)^2x^k/(k+1) are irreducible over the field of rational numbers. - Zhi-Wei Sun, Mar 23 2013
ζ(7) is irrational.
Conjecture: a(n) > 0 for all n ≥ 1.
Conjecture: a(n) > 0 for all n > 5.
Conjecture: a(n) > 0 for all n > 1 with the only exception n = 8.
Conjecture: a(n) > 0 if n is different from 1, 6, 16, 24.
Conjecture: a(n) > 0 for all n > 1.
Conjecture: a(n) > 0 for all n > 1.
The pebbling number conjecture: the pebbling number of a Cartesian product of connected graphs is at most equal to the product of the pebbling numbers of the factors. See Asplund, Hurlbert, and Kenter.
Pfister's problem (Problem 1 of [Pfister1971, §4]): what is the true value of p(ℝ(X_1, …, X_n)), as a function of n?
The Pierce-Birkhoff conjecture states that for every real piecewise-polynomial function f : ℝⁿ → ℝ, there exists a finite set of polynomials gᵢⱼ ∈ ℝ[x₁, ..., xₙ] such that f = supᵢ infⱼ(gᵢⱼ).
There are infinitely many Pierpont primes.
Pittel conjectures that if d_n ≥ 1 and d_n/n → 0, then the second moment of the number S_n of stable matchings is O((E[S_n])^2). The bound may depend on the sequence d_n.
Pittel conjectures a threshold p_(n) for the rank pairs across stable matchings to trace out a hyperbola. For all sufficiently large n, it lies between 9/4(log n)^2/n and 1. The fixed reciprocal arc (t,t^-1) for t ∈ [2/3,3/2] specifies the curve to cover in this formulation.
Pollock's (tetrahedral numbers) conjecture: every integer is the sum of at most 5 tetrahedral numbers.
Is the square-root sum problem polynomial time (single sum version)? Reference: Wikipedia
The integer factorization problem: Can the prime factorization of a positive integer be computed in polynomial time? We state the problem by asking if Nat.primeFactorsList is polynomial-time computable (assuming typical encodings of ℕ and List ℕ into bitstrings). Reference: Wikipedia
Conjecture: every odd number, beginning with 3, is the sum of a prime number and a practical number. - Hal M. Switkay, Jan 28 2023
Conjecture: a(n) > 0 for all n > 1075.
Are there infinitely many tuples of three consecutive primes (p, q, r) such that r - p = 6?
For any k ≥ 2, let a₁,...,aₖ and b₁,...,bₖ be integers with aᵢ > 0. Suppose that for every prime p there exists an integer n such that p ∤ ∏ i, (aᵢ n + bᵢ). Then there exist infinitely many n such that aᵢ n + bᵢ is prime for all i.
It is conjectured that for all n > 2, a(n) = 0 implies that 7n+6 = a(n+1) is prime, cf. A186259.
Starting at a positive value other than a(0) = 1, does this sequence ever go into a loop? The positivity hypothesis is required because the source recurrence uses the one-based prime index p₁ = 2; the x = 0 branch above is only an artifact of making aStartAt total on ℕ.
Are there infinitely many primes p such that p - 1 is a perfect square? In other words: Are there infinitely many primes of the form n^2 + 1?
Conjecture (A81091): There are infinite primes of the form 2^n + 2^i + 1, with 0 < i < n.
"Conjecture: all elements of this sequence are greater than 0."
Conjecture: a(n) > 0 for all n > 2732.
Conjecture: a(n) > 0 for all n > 6.
Zhi-Wei Sun's Conjecture (A239957): Every prime p has a primitive root 0 < g < p of the form k^2 + 1, where k is an integer.
It is unknown whether or not numbers in this sequence are always squarefree. - _John M. Campbell_, Apr 21 2011
Conjecture: For x > 10^9, the most frequent value in a(n), n=1… x, has form 120k.
SAT has no p-optimal proof system (Pudlák's conjecture SAT [Pu17]). No proof system for SAT p-simulates every other proof system for SAT.
Quasiperfect Numbers Conjecture. Do quasiperfect numbers exist?
Lehmer's conjecture: τ(n) ≠ 0 for all n > 0.
The open problem: determine the Ramsey number R(5,5). It is known that 43 ≤ R(5,5) ≤ 46.
Does there exist a point in the plane at rational distance from all four vertices of the unit square?
“I conjecture that every number eventually appears” — N. J. A. Sloane, OEIS A005132. Sloane later added that he was no longer sure every number appears. The coverage question remains open and is formalized here as surjectivity onto the natural numbers.
All numbers appear infinitely often, i.e., for every number k ≥ 0 and every frequency f > 0 there is an index i such that a(i) = k is the f-th occurrence of k in the sequence. - _Klaus Brockhaus_, Aug 29 2006
Conjecture, (i): S_n(x) is irreducible over the field of rational numbers for every n = 1, 2, 3, … - _Zhi-Wei Sun_, Mar 20 2013
Conjecture: For prime p such that p-2 is not a prime, a(p-1) = p. - _Bill McEachen_, Sep 26 2025
Conjecture: the sequence contains 8 zeros.
For a graph G, we define Δ(G) to be the maximum degree, ω(G) to be the size of the largest clique subgraph, and χ(G) to be the chromatic number. Reed's omega, delta, and chi conjecture states that χ(G) ≤ ⌈ 1/2(ω(G) + Δ(G) + 1) ⌉.
Conjecture (i): a(n) > 0 for all n > 0.