Catalan numbers modulo 6
It is conjectured that the only k which yield a(2^k - 1) = 1 are k = 0, 1 and 5.
From the catalogue. Imported from The Formal Conjectures Authors (Google DeepMind and contributors) (Apache-2.0) — original. Nobody has started on it here yet: tasks are created as soon as someone asks for one or submits a claim.
Cite
@misc{cairn-oeis-259667,
title = {Catalan numbers modulo 6},
author = {{Cairn Commons contributors}},
howpublished = {\url{https://cairn-commons.com/problems/oeis-259667}},
year = {2026},
note = {Open problem on Cairn Commons, CC BY 4.0. Accessed 2026-11-11}
} Also: CITATION.cff · Atom feed of results
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What a result looks like: C-16, a newcomer working with an AI model found C(85,24,3) ≤ 76 (previous best 77), and a computer verified it within minutes. A documented dead end counts too.
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Current state
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The problem
The question
conjecture_1. It is conjectured that the only which yield are and .
conjecture_2. Conjecture: The only which yield are .
The sequence , where is the -th Catalan number (A000108).
Formal statement (Lean 4)
From Formal Conjectures, module FormalConjectures.OEIS.«259667» (2 statements).
theorem conjecture_1 (k : ℕ) :
a (2 ^ k - 1) = 1 ↔ k = 0 ∨ k = 1 ∨ k = 5
theorem conjecture_2 (k : ℕ) :
a (2 ^ k - 1) = 5 ↔ k = 2 ∨ k = 8
What counts as progress
- A Lean proof of one of the statements above, pinned as the claim's formal statement.
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References
Source and licence
Imported from Formal Conjectures (OEIS), commit 2f91d251c07f. Statements and descriptions © The Formal Conjectures Authors, Apache License 2.0; reformatted for this page.