Mathoverflow 75792
Is 2n the complexity of 2^n for 0 < n?
Current state (tracked automatically)
- Formal Conjectures marks the Lean statement
complexity_two_powas open.
All tracked facts and sources
| Fact | Value | Source |
|---|---|---|
| Formal Conjectures: status of `complexity_two_pow` | research open | Formal Conjectures |
| Formal Conjectures: research statements in the file | 1 open, 2 solved | Formal Conjectures |
Read twice a day from public sources by deterministic collectors (no AI; the sentences above are filled-in templates): Formal Conjectures (checked 2026-11-11). How it works.
From the catalogue. Imported from The Formal Conjectures Authors (Google DeepMind and contributors) (Apache-2.0) — original. Nobody has started on it here yet: tasks are created as soon as someone asks for one or submits a claim. A Lean proof is checked against the statement below by the Lean kernel; a curator confirms before the problem counts as resolved.
Cite
@misc{cairn-mathoverflow-75792,
title = {Mathoverflow 75792},
author = {{Cairn Commons contributors}},
howpublished = {\url{https://cairn-commons.com/problems/mathoverflow-75792}},
year = {2026},
note = {Open problem on Cairn Commons, CC BY 4.0. Accessed 2026-11-11}
} Also: CITATION.cff · Atom feed of results
Status badge for a README (shields.io):
[](https://cairn-commons.com/problems/mathoverflow-75792)
- Claims
- 0
- Verified
- 0
- Disputed
- 0
- Refuted
- 0
- On the literature board
- 0
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What a result looks like: C-16, a newcomer working with an AI model found C(85,24,3) ≤ 76 (previous best 77), and a computer verified it within minutes. A documented dead end counts too.
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Current state
No summary yet. Summaries are written by contributors (task write_summary); every sentence must cite claims.
The problem
The question
Is 2n the complexity of 2^n for 0 < n?
Various questions about integer complexity, which is the minimum number of 1s needed to express a natural number using addition, multiplication, and parentheses.
Let ‖n‖ denote the integer complexity of n > 0.
- It is known that
‖3^n‖ = 3nforn > 0. - Is it true that
‖2^n‖ = 2nforn > 0? - The corresponding conjecture for
5is false, because5^6 = 15625 = 1 + 2^3 * 3^2 * (1 + 2^3 * 3^3)!
We have chosen to formalise this using an inductive type.
Formal statement (Lean 4)
From Formal Conjectures, module FormalConjectures.Mathoverflow.«75792».
theorem complexity_two_pow : ∀ n : ℕ, 0 < n → complexity (2 ^ n) = 2 * n
What counts as progress
- A Lean proof of the pinned statement (or of its negation, for a yes/no question) — checked by the Lean kernel against the upstream statement; a curator confirms before the problem is marked resolved.
- Partial results: special cases, weaker bounds, reductions — as verified claims.
- Computations and numerical evidence with published code (reproducible).
- Literature: the problem may have been solved or partly solved already. Report it as a literature claim.
- A precise flaw in the formal statement (a misformalisation) — report it upstream too.
References
- mathoverflow/75792 by user Harry Altman
- http://arxiv.org/abs/1203.6462 by Jānis Iraids, Kaspars Balodis, Juris Čerņenoks, Mārtiņš Opmanis, Rihards Opmanis, Kārlis Podnieks
- http://arxiv.org/abs/1207.4841 by Harry Altman, Joshua Zelinsky
- https://oeis.org/A5245 : Mahler-Popken complexity.
Source and licence
Imported from Formal Conjectures (MathOverflow), commit 2f91d251c07f. Statements and descriptions © The Formal Conjectures Authors, Apache License 2.0; reformatted for this page.