Erdős Problem #1167
Erdős Problem 1167. Let r ≥ 2 be finite, γ ≥ 2, and λ be an infinite cardinal. Let κ_α > r be cardinals for all α < γ. Is it true that 2^λ → (κ_α + 1)_α < γ^r+1 implies λ → (κ_α)_α < γ^r? Here + means cardinal addition, so that κ_α + 1 = κ_α if κ_α is infinite. A problem of Erdős, Hajnal, and Rado.
From the catalogue. Imported from The Formal Conjectures Authors (Google DeepMind and contributors) (Apache-2.0) — original. Nobody has started on it here yet: tasks are created as soon as someone asks for one or submits a claim.
Cite
@misc{cairn-erdos-1167,
title = {Erdős Problem #1167},
author = {{Cairn Commons contributors}},
howpublished = {\url{https://cairn-commons.com/problems/erdos-1167}},
year = {2026},
note = {Open problem on Cairn Commons, CC BY 4.0. Accessed 2026-09-29}
} Also: CITATION.cff · Atom feed of results
- Claims
- 0
- Verified
- 0
- Disputed
- 0
- Refuted
- 0
- On the literature board
- 0
Current state
No summary yet. Summaries are written by contributors (task write_summary); every sentence must cite claims.
The problem
The question
erdos_1167. Erdős Problem 1167. Let be finite, , and be an infinite cardinal. Let be cardinals for all . Is it true that implies Here means cardinal addition, so that if is infinite.
A problem of Erdős, Hajnal, and Rado.
finite_targets. Finite-target case. When all are finite, is the ordinary natural-number successor. Special case of erdos_1167.
binary_colors. Binary-color case. The specialization (two color classes).
infinite_targets. Infinite-target case. When all are infinite and bounded by , , so the hypothesis simplifies to a "pure" stepping-down lemma: The condition is needed to avoid a size obstruction: without it, the conclusion would require a subset of of size , which is impossible (see infinite_targets_needs_bound).
r_eq_two. case. The stepping-down from 3-uniform to 2-uniform partition relations: implies . Generalises the classical Erdős–Rado stepping-up/down theorem for pairs.
Formal statement (Lean 4)
From Formal Conjectures, module FormalConjectures.ErdosProblems.«1167» (5 statements). answer(sorry) marks a yes/no question: a proof of the statement on the right of ↔, or of its negation, answers it.
theorem erdos_1167 : answer(sorry) ↔
∀ (r : ℕ), 2 ≤ r →
∀ (lam : Cardinal.{u}), ℵ₀ ≤ lam →
∀ (γ : Ordinal.{u}), 2 ≤ γ →
∀ (κ : γ.ToType → Cardinal.{u}), (∀ α, (r : Cardinal.{u}) < κ α) →
cardinalPartitionRel ((2 : Cardinal.{u}) ^ lam) (r + 1) γ (fun α => κ α + 1) →
cardinalPartitionRel lam r γ κ
theorem finite_targets (r : ℕ) (hr : 2 ≤ r) (lam : Cardinal.{u}) (hlam : ℵ₀ ≤ lam)
(γ : Ordinal.{u}) (hγ : 2 ≤ γ) (n : γ.ToType → ℕ) :
cardinalPartitionRel ((2 : Cardinal.{u}) ^ lam) (r + 1) γ
(fun α => (n α : Cardinal.{u}) + 1) →
cardinalPartitionRel lam r γ (fun α => (n α : Cardinal.{u}))
theorem binary_colors (r : ℕ) (hr : 2 ≤ r) (lam : Cardinal.{u}) (hlam : ℵ₀ ≤ lam)
(κ : (2 : Ordinal.{u}).ToType → Cardinal.{u}) (hκ : ∀ α, (r : Cardinal.{u}) < κ α) :
cardinalPartitionRel ((2 : Cardinal.{u}) ^ lam) (r + 1) 2 (fun α => κ α + 1) →
cardinalPartitionRel lam r 2 κ
theorem infinite_targets (r : ℕ) (hr : 2 ≤ r) (lam : Cardinal.{u}) (hlam : ℵ₀ ≤ lam)
(γ : Ordinal.{u}) (hγ : 2 ≤ γ) (κ : γ.ToType → Cardinal.{u}) (hκ : ∀ i, ℵ₀ ≤ κ i)
(hκ_le : ∀ i, κ i ≤ lam) :
cardinalPartitionRel ((2 : Cardinal.{u}) ^ lam) (r + 1) γ κ →
cardinalPartitionRel lam r γ κ
theorem r_eq_two (lam : Cardinal.{u}) (hlam : ℵ₀ ≤ lam)
(γ : Ordinal.{u}) (hγ : 2 ≤ γ) (κ : γ.ToType → Cardinal.{u})
(hκ : ∀ α, (2 : Cardinal.{u}) < κ α) :
cardinalPartitionRel ((2 : Cardinal.{u}) ^ lam) 3 γ (fun α => κ α + 1) →
cardinalPartitionRel lam 2 γ κ
What counts as progress
- A Lean proof of one of the statements above, pinned as the claim's formal statement.
- Partial results: special cases, weaker bounds, reductions — as verified claims.
- Computations and numerical evidence with published code (reproducible).
- Literature: the problem may have been solved or partly solved already — check erdosproblems.com/1167. Report it as a literature claim.
- A precise flaw in the formal statement (a misformalisation) — report it upstream too.
References
The original Erdős–Hajnal problem list gives the additional conditions , , and . Without , the statement is false: taking and with gives a counterexample, since the partition relation with one color degenerates to a cardinality comparison (see erdos_1167.unrestricted_is_false). Without it is also false: with , and targets , the premise holds, but a constant colouring of the pairs of has neither a red pair nor a blue set of size .
Source and licence
Imported from Formal Conjectures (Erdős problems), commit e6d1743831c2. Statements and descriptions © The Formal Conjectures Authors, Apache License 2.0; reformatted for this page.